CSES Subarray Sums II

So I was trying to solve this CSES problem, but I couldn’t, so I looked at the editorial for a bit of help. I read the idea behind the solution and tried making a solution using sets instead of maps. Here is my solution,

#include <bits/stdc++.h>
using namespace std;
long long n,tar;
long long ans=0;
int main(){
    cin >> n>>tar; //Get the input for the problem
    long long arr[n+1];//Prefix array
    set<long long> track={0};//keeps track if the sum we need is there
    arr[0]=0;
    for(int i=1;i<=n;i++){
        long long j;
        cin >>j;
        arr[i]=arr[i-1]+j;
        if(track.count(arr[i]-tar)) ans++;//If the set has the opposite answer, then add
        track.insert(arr[i]);//Insert this for future cases
    }
    
    cout << ans << "\n";
    return 0;
} 

The idea behind the solution is the same, but I used sets. The solution works for most test cases except a few. Can you guys tell me why? Thanks!!

Because it’s wrong.

Ok thanks. I’ll try to fix it.

a set removes duplicate elements

yeah, I just noticed that. I solved it finally